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Thursday, 26 May 2016

C11: CALCULATION FOR REVERBERATION TIME FOR A THEATER BUILDING/AUDITORIUM/MUSIC RECORDING ROOM

REVERBERATION:
          The sound produced in a room or a hall suffers multiple reflections from the various walls, ceilings and floor of the wall, so that in addition to the direct sound . A listener in the hall hears a series of sound waves.
The listener feels the persistence of sounds for sometime even the original sound has ceased. This is known as reverberation.
REVERBERATION TIME:
          It is time taken for the sound to fall below the minimum audibility measured from the instant  when the source has stopped.
SABINE’S LAW:
          This law states that the standard reverberation time is taken by the intensity of sound to fall to one millionth ( 10 -6) of its original value after the source of sound is cut off.
          T = 0.165V/ E al s l
Where,
          V= Volume of the hall
          E al s l – Total absorbing power of the room or coefficient of absorption.
MEASUREMENT OF REVERBERATION TIME:
          Sabine used an organ pipe of frequency 512Hz as his source of sound stopwatch. The stopwatch was start ear instant when the source of sound ceased to act and stopped at the instant when the sources just becomes inaudible. The ( ‘T’) can be determined.
IMPORTANCE OF REVEBERATION TIME:
          The reverberation time in a hall should not be too large and also should not be too short. If the reverberation time is too short, the sound may not be sufficiently loud in all portions of the hall should “dead” on the other hand.



These Satisfactory times are ,
SPEACHES
0.5 SECONDS
Music
1 to 0.2 Seconds
Theaters
1.1  to 0.15 Seconds

CONTROL OF REVERBERATION TIME :
·        The Reverberation time can be controlled by the following factors.
·        Providing windows and ventilators.
·        Covering the ceilings, part of the walls and even back of the chairs      with absorbent material like felt, glass wool etc.,
·        Using heavy curtains with folds and covering the floor with carpets.

·        Having a good sized audience.

REQUIREMENT OF A GOOD SOUND ABSORBING MATERIALS :
A good  sound absorbing material should have the following requirements :
Ø It should have high sound absorbing efficiency.
Ø It should be efficient over a wide range of frequencies.
Ø It should be easy to fix.
Ø It should be cheap and easily available.
Ø It should have a good resistance to fire.
ABSORPTION CO- EFFICIENT AND ITS MEASUREMENT:
          The Coefficient of absorption of materials is the ration of sound energy absorbed by the surface to that of the total incident sound energy on the surface. Absorption coefficient = Sound energy absorbed by surface / Total sound energy incident of the surface.
MATERIALS
ABSORBTION CO-EFFICIENT
Marble
0.01
Glass
0.02
Brick wall
0.03
Wooden floor
0.06
Carpet
0.15 to 0.30
Ordinary Chair
0.17
Hair or Flat ( 2.5 cm thick )
0.58
Open Window
1.3
Human Body
4.3 – 4.7

CALCULATION OF REVERBERATION TIME 


GIVEN DATA:
          Size of stage         = 15.7 x 4.60m
          Size of hall           = 15.7 x 22.80m
Reverberation time :
Area of  stage                = 15.7 x 4.60m
                                      = 78.4 m2
Volume of stage            = 78.4 x 5.60
                                       = 439.04m3
Area of hall                    = 15.7 x 22.8
                                       = 364.80m2
Volume of hall               = 364.80 x 6.50
                                      = 2371.2m3
Total volume                 = 439.04+2371.2
                                      = 2810.24m3
Floor Area                     = ( 22.8 x 16 )+( 16x 4.9 )
                                      = 443.2m2
Ceiling area                  = ( 22.8 x 16) + ( 16 x 4.9 )
                                      = 443.2m2
Stage                             = (16 x 5.6) + 2(4.9 x 5.6)
                                      = 144.48m2
Hall                                = ( 16 x 6.5 ) + 2 ( 22.8 x 6.5 )
                                      = 400.4m2
Total                               = 544.88 m2

Coefficient of wall          = 0.30
Coefficient of ceiling      = 0.8
Coefficient of floor         = 0.06
Area ( A )                       = ( 0.3 x 544.88 )+ ( 0.8 x 443.2 )+ ( 0.06 x 443.2)
                                                (544.88+443.2 +443.2)
                                      = 0.278
Reverberation time : T   = 0.167 V/ as

          S                           = 544.88 + 443.2 + 443.2
                                      = 1441.28
          T                          = (0.167 x 2810.24) / (0.278 x 1431.28)
                                      = 1.18 Sec < 1.5 Sec.
                             Hence Ok.

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